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AMC8每日一题(2000年真题#06)

2018-04-10
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2000 AMC 8 竞赛试题/第6题

Problem

What is the minimum possible product of three different numbers of the set{-8，-6，-4，0，3，5，7} ?

(A) -336 (B) -280 (C) -210 (D) -192 (E) 0

Solution

The only way to get a negative product using three numbers is to multiply one negative number and two positives or three negatives. Only two reasonable choices exist:(-8)x(-6)x(-4)=(-8)x(24)=-192 and (-8)x5x7=(-8)x35=-280. The latter is smaller, so (B)-280.